Dear all,
this question has already been answered, but I did not understand the answer. Maybe I am too bad at adding single digit numbers. (Sorry Ted, you answered here already viewtopic.php?f=15&t=2931&p=11969&hilit ... rea#p11969 .)
Following this table https://www.neuron.yale.edu/neuron/stat ... chart.html
the membrane current density has a unit of mA/cm^2 = E3 A / E4 m^2 = E1 A/m^2
the area of a segment has an area of um^2 = E12 m^2
when I multiply those, I get E1 A/m^2 * E12 m^2 = E11 A
so to obtain the current in nA (E9), I would multiply this with E2, meaning a multiplication by a factor of 100.
In previous code and posts here, I saw a factor of 1/100. This would be obtained, if one took cm^2 as E2 m^2 and um^2 as E6 m, ignoring that it's squared?
Thanks!
Membrane current scaling

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Re: Membrane current scaling
If you've lost your chem class notes about unit conversion, maybe the following will help.
1 megabuck is one million dollars.
1 grand = 1e3 megabucks.
1 buck = 1e6 megabucks.
So if you had N bucks and wanted to know how many grand that was,
your reasoning would be
"1 buck is 1e6 megabucks, and 1 grand is 1e3 megabucks, so to convert bucks to grand I'd multiply the number of bucks by a factor of 1000."
Try that on your bookie and see what happens.
The way to think clearly about this is to start with the identities
1 grand / 1e3 megabucks = 1
1 buck / 1e6 megabucks = 1
Then realize that
1 grand / 1e3 megabucks = 1 buck / 1e6 megabucks
rearrange
1 grand / 1 buck = 1e3 megabucks / 1e6 megabucks
eliminate the common unit factor on the right hand side
1 grand / 1 buck = 1e3 / 1e6
multiply the right hand side by 1e6/1e6 (i.e. by 1)
1 grand / 1 buck = 1000
and finally divide both sides by 1000 to get the identity
1 grand / 1000 bucks = 1
Suppose Joe says he has 3 grand. How many bucks is that? Multiply by a ratio that equals 1. What ratio is that? 1000 bucks / 1 grand
3 grand * 1000 bucks / 1 grand = 3000 bucks (the grands in the numerator and denominator cancel out, leaving bucks)
And if Louie says he has 25 bucks, how many grand is that?
25 bucks * 1 grand / 1000 bucks = 0.025 grand (the bucks cancel out, and Louie might get canceled out himself if his bookie expected a grand).
Now that your unit conversion skills are on a par with those of a bookie, you're ready to tackle the sterile world of um, cm, nA, mA/cm2 and all that. Be careful, thoughit'll take some practice before your unit conversion expertise rises to the level of a narcotraficante.
1 megabuck is one million dollars.
1 grand = 1e3 megabucks.
1 buck = 1e6 megabucks.
So if you had N bucks and wanted to know how many grand that was,
your reasoning would be
"1 buck is 1e6 megabucks, and 1 grand is 1e3 megabucks, so to convert bucks to grand I'd multiply the number of bucks by a factor of 1000."
Try that on your bookie and see what happens.
The way to think clearly about this is to start with the identities
1 grand / 1e3 megabucks = 1
1 buck / 1e6 megabucks = 1
Then realize that
1 grand / 1e3 megabucks = 1 buck / 1e6 megabucks
rearrange
1 grand / 1 buck = 1e3 megabucks / 1e6 megabucks
eliminate the common unit factor on the right hand side
1 grand / 1 buck = 1e3 / 1e6
multiply the right hand side by 1e6/1e6 (i.e. by 1)
1 grand / 1 buck = 1000
and finally divide both sides by 1000 to get the identity
1 grand / 1000 bucks = 1
Suppose Joe says he has 3 grand. How many bucks is that? Multiply by a ratio that equals 1. What ratio is that? 1000 bucks / 1 grand
3 grand * 1000 bucks / 1 grand = 3000 bucks (the grands in the numerator and denominator cancel out, leaving bucks)
And if Louie says he has 25 bucks, how many grand is that?
25 bucks * 1 grand / 1000 bucks = 0.025 grand (the bucks cancel out, and Louie might get canceled out himself if his bookie expected a grand).
Now that your unit conversion skills are on a par with those of a bookie, you're ready to tackle the sterile world of um, cm, nA, mA/cm2 and all that. Be careful, thoughit'll take some practice before your unit conversion expertise rises to the level of a narcotraficante.
Re: Membrane current scaling
Right, I went in the wrong direction in the end. Thanks